Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
42 views
in Chemistry by (80.6k points)
closed by
In a process, `701 J` of heat is absorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?

1 Answer

0 votes
by (80.9k points)
selected by
 
Best answer
Given `W= -394` (work done by system)
`q=701 J`
Asked `Delta E= ?`
Formula `Delta E = q+w`
Explanation `Delta E=` Change in internal energy
`q="heta"`
`w="work"`
Substitution & calculation
`:. Delta E= 701+(-394)=307 J`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...