Question

Consider the following two reactions:
i. Propene `+H_(2) rarr` Propane, `DeltaH_(1)`
ii. Cyclopropane `+H_(2) rarr` Propane, `DeltaH_(2)` Then, `DeltaH_(2) - DeltaH_(1)` will be:

Answer 1

Correct Answer - B
`CH_(3)-CH=CH_(2)+H_(2)toCH_(3)-CH_(2)-CH_(3),DeltaH_(1)=(BE_(C=C)+BE_(H-H))-(2BE_(C-H)+BE_(C-C))`
`+H_(2)toCH_(3)-CH_(2)-CH_(3),`
`DeltaH_(2)=(BE_(C-C)+BE_(H-H))-(2xxBE_(C-H))`
`DeltaH_(2)-DeltaH_(1)=2BE_(C-C)-BE_(C=C)`