Correct Answer - 2
`w_(d)`=Work done along dotted line
`=sumPDeltaV`
`=4xx1.5+1xx1+2.5xx(2)/(3)=8.65L` atm
`w_(s)`=It is reversible isothermal process
`2.303nRTlog((V_(2))/(V_1))`
`=2.303xx(PV)log((V_(2))/(V_(1)))`
`=2.303xx2log((5.5)/(0.5))=4.79L" "atm`
`(w_(d))/(w_(s))=(8.65)/(4.79)~~2`