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Calculate the amount of lime that can be produced by heating 100g to 90% pure limestone

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Correct Answer - a,c
`underset(100g)(CaCO_(3)) to underset(56g)(CaO)+CO_(2)`
`therefore "100g of "CaCO_(3)-=56"g "CaO`
`therefore "90g "CaCO_(3)-=(56)/(100)xx90"g "CaO=(50.4)/(56)=0.9`

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