Correct Answer - d,d
The reaction involed is
`underset("64g")underset("1mol")(underset("120g")underset("1mol")underset("milky")(CaSO_(3))+H_(2)O+SO_(2) to underset("colourless")(Ca(HSO_(3))_(2)))`
`12"g "CaSO_(3) "will react with" 6.4g"SO_(2) or 0.1"mol" SO_(2)`