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in Physics by (92.4k points)

At ordinary temperature, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures they may also have vibrational energy. As a result of this at higher temperatures (C= molar heat capacity at constant volume) :–

(a) Cv = 3R/2  for a monoatomic gas

(b) Cv > 3R/2 for a monoatomic gas

(c) Cv > 5R/2 for a diatomic gas

(d) Cv = 5R/2 for a diatomic gas

1 Answer

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by (83.5k points)
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Best answer

Correct option (c) Cv > 5R/2 for a diatomic gas

Explanation:

 Monoatomic gas Cv = 3R/2

This value is same for high temperature also, In case of diatomic gas

Cv = 5R/2 (at low temperature)

Also,Cv > 5R/2  (at high temperature due to vibrational kinetic energy)

by (10 points)
Can you please elaborate this answer

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