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The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^(2)`. If the conductance of benzoate ion and `H^(+)` ion are `12` and `288.42 ohm^(-1) cm^(2)` respectively. Its degree of dissociation is :
A. 0.39
B. `3.9 %`
C. `0.35 %`
D. `0.039 %`

1 Answer

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Best answer
Correct Answer - B
`alpha=(Lambda_(m))/(Lambda_(m)^(@))=12.8/((42+288.42))=0.0387`

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