The vector equation of the plane passing ; through A(\(\bar{a}\)) and perpendicular to \(\bar{n}\) is \(\bar{r}.\bar{n} = \bar{a}.\bar{n}.\)
M(1, 0, 0) is the foot of the perpendicular drawn from origin to the plane. Then the plane is passing through M : and is perpendicular to OM.
If \(\bar{m}\) is the position vector of M, then \(\bar{m}\) = \(\hat{i}\)
Normal to the plane is
∴ the vector equation of the required plane is \(\bar{r} . \hat{i} = 1\)
