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The sides of a triangle ABC lie on the lines `3x + 4y = 0, 4x +3y =0` and `x =3` . Let `(h, k)` be the centre of the circle inscribed in `triangleABC`

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The sides of a triangle ABC lie on the lines `3x + 4y = 0, 4x +3y =0` and `x =3` . Let `(h, k)` be the centre of the circle inscribed in `triangleABC`. The value of `(h+ k)` equals
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The equation of the angle bisector of angle A is
`(3x+4y)/(5) = +-(4x+3y)/(5) " or " x=+-y`
image
The equation of internal bisectors is x=-y
Since h and k lie on the line x = -y, we have
h+k=0
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