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If for `x (0,1/4),` the derivative of `tan^(-1)((6xsqrt(x))/(1-9x^3))` is `sqrt(x)dotg(x),` then `g(x)` equals: `(3x)/(1-9x^3)` (2) `3/(1+9x^3)` (3) `9/(1+9x^3)` (4) `(3xsqrt(x))/(1-9x^3)`
A. `(3)/(1+9x^(3))`
B. `(9)/(1+9x^(3))`
C. `(3xsqrt(x))/(1-9x^(3))`
D. `(3x)/(1-9x^(3))`

1 Answer

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Best answer
We have
`y=tan^(-1)((6xsqrt(x))/(1-9x^(3)))`
`=tan^(-1)((2cdot(3x^(3//2)))/(1-(3x^(3//2))^(2)))=2 tan ^(-1)(3x^(3//2))`
`therefore" "(dy)/(dx)=2xx(1)/(1+9x^(3))xx3xx(3)/(2)xxx^(1//2)=(9sqrt(x))/(1+9x^(3))`
`therefore" "g(x)=(9)/(1+9x^(3))`

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