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IUPAC namd of [Cr(H2O)4Cl2]Cl is 

(a) tetraaquadichlorochromate 

(b) tetraaquadichlorochromium (III) Chloride 

(c) tetra aquadichlorochromium (II) chloride 

(d) dichlorotetraaquachromium (III) chloride

1 Answer

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Best answer

Correct option (b) tetraaquadichlorochromium (III) Chloride    

Explanation:

Alphabetlically ligand is written first with ending at -O- followed by metal ending at ium and then negative end of coordination compound.

tetra aqua  for 4H2O

dichloro  for 2 Cl

chromium (III)  for Cr3+

Chloride  for ClΘ

IUPAC name = tetraaquadichlorchromium (III) chloride

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