Let X = number of successes.
p = probability of success in a single trial
∴ p = 0.01 and q = 1 – p = 1 – 0.01 = 0.99
∴ X ~ B(n, 0.01)
The p.m.f. of X is given by
P(at least one success)
Hence, the number of trials required in order to have a probability greater than 0.5 of getting at least one success is \(\frac{log\, 0.5}{log\,0.99}\) or 68.