Let X = number of defective items.
p = probability of defective item
The p.m.f. of X is given by
P(sample of 10 items will include not more than one defective item) = P[X ≤ 1]
Hence, the probability that a sample of 10 items will include not more than one defective item = 29\(\left(\frac{19^9}{20^{10}}\right).\)