Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
62 views
in Chemistry by (93.9k points)
closed by
Calculate the boiling point of solution when 4g of Mg `SO_(4) (M=120g "mol"^(-1))` was dissolved in 100g of water, assuming `MgSO_(4)` undergoes complete ionization
`(K_(b) " for water " = 0.52 K " kg mol"^(-1))`

1 Answer

0 votes
by (91.1k points)
selected by
 
Best answer
`DeltaT_(b) = iK_(b) xx m`
`T_(S)- Ti = (i xx 0.52 xx WB)/(M_(g) xx W_(A)(Kg))`
`i=2, M_(B) = 120 g//"mol" W_(B) = 4g, W_(A) = 100`
`T_(S) - 100= (2 xx 0.52 xx 4 xx 1000)/(120 xx 100)`
`T_(S)-100 = 0.346`
`T_(S) = 100+0.346`
`T_(S) = 100.346 ""^(@)C`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...