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Calculate average deviation from the data of marks obtained by 10 students .
90 , 64 , 79 , 33 , 85 , 59 , 60 , 70 , 40, 95

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`barX = (675)/(10) = 67.5`
A.D= `(sum|x|)/(N) = (163)/(10) = 16.3`

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