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+1 vote
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A vessel of volume V = 7.5 1 contains a mixture of ideal gases at a temperature T = 300 K: v1 = 0.10 mole of oxygen, v2 = 0.20 mole of nitrogen, and v3 = 0.30 mole of carbon dioxide. Assuming the gases to be ideal, find:

(a) the pressure of the mixture;

(b) the mean molar mass M of the given mixture which enters its equation of state pV = (m/M) RT, where m is the mass of the mixture.

1 Answer

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Best answer

(a) The mixture contains v1 , v2 and v3 moles of O2, N2 CO2 respectively. Then the total number of moles of the mixture

v = v1+v2+v3

 we know, ideal gas equation for the mixture

(b) Mass of oxygen (O2) present in the mixture : m1 = v1 M1

Mass of nitrogen (N2) present in the mixture : m2 = v2 M2

Mass of carbon dioxide (CO2) present in the mixture : m3 = v3 M3

So, mass of the mixture

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