Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
92 views
in Mathematics by (93.9k points)
closed by
If the roots of equation `(a + 1)x^2-3ax + 4a = 0` (a is not equals to -1) are greater than unity, then
A. `[-(10)/(7),1]`
B. `[-(12)/(7),0]`
C. `[-(16)/(7),-1)`
D. `(-(16)/(7),0)`

1 Answer

0 votes
by (91.1k points)
selected by
 
Best answer
Correct Answer - C
`(c )` `(a+1)x^(2)-3ax+4a=0`
`D=9a^(2)-16a(a+1) ge 0` ………`(i)`
`x_(1) gt 1`, `x_(2) gt 1`
`:. (a+1)f(1) gt 0` and `(3a)/(2(a+1)) gt 1`
`implies(a+1)(2a+1) gt 0`
and `(a-2)/(a+1) gt 0` ……..`(ii)`
`(2a+1)/(a+1) gt 0`………`(iii)`
Solving `(i)`, `(ii)` and `(iii)`, we get `-(16)/(7) le a lt -1`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...