Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
319 views
in Mathematics by (94.1k points)
closed by
If the quadratic equation `x^(2)-36x+lambda=0` has roots `alpha` and `beta` such that `alpha`, `beta in N` and `(lambda)/(5) cancel in Z` and `lambda` assumes minimum possible value then `(sqrt(alpha+2)sqrt(beta+2))/(|alpha-beta|)` is equal to
A. `(3)/(8)`
B. `(3)/(16)`
C. `(sqrt(111))/(34)`
D. `(sqrt(111))/(17)`

1 Answer

0 votes
by (91.2k points)
selected by
 
Best answer
Correct Answer - A
`(a)` `x^(2)-36x+lambda=0`
`:. Lambda=36x-x^(2)`
`alpha=1`, `lambda=5`, `beta=35` (rejected)
image
`:.alpha=2`, `lambda=68`, `beta=34` or `alpha=34`, `beta=2`
`:. (sqrt(36)sqrt(4))/(32)=(3)/(8)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...