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`5` different objects are to be distributed among `3` persons such that no two persons get the same number of objects. Number of ways this can be done is,
A. `60`
B. `90`
C. `120`
D. `150`

1 Answer

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Best answer
Correct Answer - B
`(b)` Division of objects can be `(0,1,4)` or `(0,2,3)`
So total number of distribution ways
`=(5!)/(0!*1!*4!)xx3!+(5!)/(0!*2!*3!)xx3!`
`=30+60=90` ways

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