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i) for min time the car should use max acceleration and now car will travel 40+40+3+17=100m 

using newtons 2nd eqn 

100=v(rel)t=1/2at2

100=0+t2/4 

t=20s 

ii) Total distance travelled by car = S = 100 + 20*20 = 500m

iii) The final speed of the car

v = u+at

v = 20+0.5*20 = 30 m/s

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