Let X = number of working discs.
p = probability that a floppy disc works
The p.m.f. of X is given by
(i) P(none of the floppy discs work) = P(X = 0)
Hence, the probability that none of the floppy disc will work = 1/203.
(ii) P(exactly one floppy disc works) = P(X = 1)
Hence, the probability that exactly one floppy disc works = 3(19/203)
(iii) P(exactly two floppy discs work) = P(X = 2)
Hence, the probability that exactly 2 floppy discs work = 3(193/203)
(iv) P(all 3 floppy discs work) = P(X = 3)
Hence, the probability that all 3 floppy discs work = (19/20)3.