Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
304 views
in CBSE by (15 points)
edited by

Balloon of volume 800 centimetre cube is filled with hydrogen gas of density 9 x 10 raise to power minus 5 gram per centimetre cube. If the empty balloon weighs 0. 3 gf and density of air is 1. 3 x 10 raise to power minus 3 gram per centimetre cube, calculate the lifting power of balloon

Please log in or register to answer this question.

1 Answer

0 votes
by (18.1k points)

Volume of balloon = V = 800 cm3

Density of hydrogen gas = pH = 9 x 10-5 g cm-3

Weight of empty balloon = 0.3 gf

Density of air = ρa = 1.3 x 10-3 g cm-3

Weight of hydrogen gas in balloon = VρHg

= 800 x 9 x 10-5 x g

= 72 x 10-3 gf

= 0.072 gf

Volume of balloon = Volume of hydrogen gas in the balloon = volume of air displaced by balloon.

Down thrust = Wt. of empty balloon + wt. of hydrogen gas in balloon

= 0.3 + 0.072 = 0.372 gf

Upthrust = Wt. of air displaced by balloon

= Vρag

= 800 x 1.3 x 10-3 x g

= 8 x 1.3 x 10-1 x g

= 10.4 x 10-1 x g = 1.04 gf

Lifting power of balloon = Upthrust - Down thrust

= 1.04 - 0.372 = 0.668 gf

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...