Question

The period of a particle in SHM is 8 s. At t = 0 it is in its equilibrium position.

(a) Compare the distance travelled in the first 4 s and the second 4 s.

(b) Compare the distance travelled in the first 2 s and the second 2 s.

Answer 1

So, distance travelled is 2A. In the next 4s it again travels 2A but from other side.

i.e., distance is travelled A in first 2s and again A in next 2s but from other side.