**Given.** L = 2m, F = 100 N,

A = 0.0225 mm^{2} = 2.25 × 10^{-8} m^{2},

Y = 2 × 10^{-11} N/m^{2},

**To find : Work (W)**

**Formula :** W = 1/2 × F × l

**Claculation :**

= antilog [log 10 – log 4.5]

= antilog [1.0000 – 0.6532 ]

= antilog [0.3468]

∴ W = 2.222 J

The work done in stretching the steel wire is 2.222 J.