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You have three resistors of values 2Ω, 3Ω and 5Ω. How will you join them so that the total resistance is more than 7Ω?

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You have three resistors of values 2Ω, 3Ω and 5Ω. How will you join them so that the total resistance is more than 7Ω?

(i) Draw a diagram for the arrangement.

(ii) Calculate the equivalent resistance.

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(ii) Requilent = R1 + R2 + R2 = 2 + 3 + 5 = 10 Ω

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