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3.7k views
in JEE by (3.3k points)
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Find the equation of the circle passing through the intersection of the circlesimageandimageand the point (3,4)

1) image

2) image

3) image

4) image

by (735 points)
We need at least 3 passing points to determine the equation of a circle. One passing point is already given. Solve the given two equation of circles to find the remaining two passing points and hence find the equation of the required circle.

1 Answer

+1 vote
by (10.8k points)
selected by
 
Best answer

The set  of circles passing through the two points of intersection is

(x-5)^2+y^2-25-k[x^2+(y-5)^2-25]=0,where k is parameter.

As the circle passes through (3,4) we can write

(3-5)^2+4^2-25-k[(3^2+(4-5)^^2-25]=0

=>4+16-25-k(9+1-25)=0

=>-5+15k=0

=>k=1/3

So the required equation of  the circle

(x-5)^2+y^2-25-1/3[x^2+(y-5)^2-25]=0

=>3x^2-30x+75-75+3y^2-x^2-y^2+10y-25+25=0

=>2x^2+2y^2-30x+10y=0

=>x^2+y^2-15x+5y=0

=>(x-15/2)^2+(y+5/2)^2=125/2

So option will be (4)None

by (3.3k points)
please solve with the help of options
by (10.8k points)
Is it OK now?
by (3.3k points)
sorry bro but answer given is option (c)
by (10.8k points)
+1
Figure supports my answer.

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