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+1 vote
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in NEET by (2.4k points)
Charges Q, 2Q,3Q and 4Q are placed at the corners  A ,B ,C ,D of a square. The direction of electric field at the centre of the square is along

A)AB

B)CB

C)BD

D)AC

3 Answers

+2 votes
by (63.2k points)
selected by
 
Best answer

Answer is B)CB

+1 vote
by (67.5k points)

Correct option(B)CB

Explanation:

Electric field at P due to charge at A is,

EA = kq/(a2/2) along AP

Electric field at P due to charge at B is,

EB = k(2q)/(a2/2) along BP

Electric field at P due to charge at C is,

EC = k(3q)/(a2/2) along CP

Electric field at P due to charge at D is,

ED = k(4q)/(a2/2) along DP

Electric field EA and EC are in opposite directions, so, their net field is,

ECA = k(3q)/(a2/2) - kq/(a2/2) = k(2q)/(a2/2) along CA

Electric field ED and EB are in opposite directions, so, their net field is,

EDB = k(4q)/(a2/2) - k(2q)/(a2/2) = k(2q)/(a2/2) along DB

Since, ECA and EDB are equal in magnitude and they are perpendicular to each other, so, their resultant E will bisect angle APB.

Or we can say it is along CB

+2 votes
by (80.8k points)

(B) CB

Solution:

by (2.4k points)
+1
Very thankyou .

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