Let BPC is a hemisphere and ABC is a cone.
Radius of hemisphere = Radius of cone
= 4/2 = 2 cm
h = Height of cone = 2 cm
= 25.12 cm3 ..........(i)
Let right circular cylinder EFGH circumscribe the given solid toy.
Radius of cylinder = 2 cm,
Height of cylinder = 4 cm
Volume of right circular cylinder = πr2 h
= 3.14 × (2)2 × 4 cm3 ...(ii)
= 50.24 cm3
∴ Required volume = Volume of cylinder – Volume of toy
= 50.24 – 25.12
= 25.12 cm3