Question

A ball is thrown upward with a certain speed. It passes through the same point at 3 second and 7 second from the start. The maximum height achieved by the ball is (1) \( 500 m \) (2) \( 250 m \) (3) \( 125 m \) (4) \( 450 m \)

Answer 1

According to the problem the ball is thrown upward.

After 3 second it will reach at the top most position within =5-3 = 2 sec

Therefore the ball will take 3+2 or 5 sec to reach at the top from the bottom.

Therefore for downward direction the motion will be,

u = 0, acceleration, a= g= 10 m/s²,  t = 5 sec

Let the maximum height is h

hence h = 1/2 x g x t² = 1/2 x 10 x 5² = 125 m