Question

could you pls tell me why we have used R=8.314×10⁷ in this question because we use R as 8.314 but in this question it is different

Answer 1

Here calculation follows CGS system taking molar mass of methane as 16g/mol and R is taken as 8.314×10⁷erg.mol^-1K^-1. Result comes in cm/s

If we take R= 8.314Jmol^-1K^-1, following SI system then molar mass of methane should be taken as 16×10^-3kgmol^-1. Then result will come in m/s