Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.8k views
in NEET by (2.4k points)
A parallel plate capacitor  is charge  to a potential  difference  of 50v. It is then discharged through  a resistance  for 2 sec and its potential  drops by 10v.   Calculate  the fraction of energy  stored in the capacitance

A) 0.14

B) 0.50

C) 0.25

D) 0.64

Please log in or register to answer this question.

1 Answer

0 votes
by (7.2k points)

The correct answer is option (d)

Explanation:

Vi = 50 v
Vf = 40 v 
we know that fraction of stored energy is given by 
[1/2 C(Vi)2] / [1/2 C(Vf)2]

= (40/50)2 = 16/25

= 0.64

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...