Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
asked in NEET by (1.9k points)
A parallel plate capacitor  is charge  to a potential  difference  of 50v. It is then discharged through  a resistance  for 2 sec and its potential  drops by 10v.   Calculate  the fraction of energy  stored in the capacitance

A) 0.14

B) 0.50

C) 0.25

D) 0.64

1 Answer

0 votes
answered by (7k points)

The correct answer is option (d)


Vi = 50 v
Vf = 40 v 
we know that fraction of stored energy is given by 
[1/2 C(Vi)2] / [1/2 C(Vf)2]

= (40/50)2 = 16/25

= 0.64

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon