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The energy  required  to charge parallel  plate condenser of plate separation d and plate area of cross section A. Such that the uniform  electric  field between the plates is E is

Ans)é E2 Ad

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1 Answer

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Energy given be the cell

E=CV 

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How the energy  is cv2.  It must be  1/2cv(square) .  Please  Explain it.....how you did it.

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