Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Chemistry by (25.4k points)
A solution containing 2.675 g of `CoCl_(3)`. 6 `NH_(3)` (molar mass = 267.5 g `"mol"^(-1)`) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of `AgNO_(3)` to give 4.78 g of AgCl (molar mass = 143.5 g `"mol"^(-1)`). The formula of the complex is (At. Mass of Ag = 108 u)
A. `[Co(NH_(3))_(6)]Cl_(3)`
B. `[CoCl_(2)(NH_(3))_(4)]Cl`
C. `[CoCl(NH_(3))_(3)]Cl_(3)`
D. `[CoCl(NH_(3))_(5)]Cl_(2)`

Please log in or register to answer this question.

1 Answer

0 votes
by (25.6k points)
Correct Answer - A

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...