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+1 vote
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in Physics by (44.6k points)

A uniform rod AB, 12 m long weighing 24 kg, is supported at end B by a flexible light string and a lead weight (of very small size) of 12 kg attached at end A. The Rod float in water with one-half of its length submerged. For this situation, mark out the correct statement. (Take g = 10 m/s2, density of water = 1000 kg/m3)

(a) The tension in the string is 36 g

(b) The tension in the string is 12 g

(c) The volume of the rod is 6.4 x 10-2 m3

(d) The point of application of the buoyancy force is passing through C (centre of mass of rod)

1 Answer

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by (67.5k points)
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Best answer

Correct option (c) The volume of the rod is 6.4 x 10-2 m3

Explanation :

For translational equilibrium 

T + B = 12 g + 24 g

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