Area of circle = πr2
But area is given to be 25π sq.cm.
∴ 25π = πr2
∴ r2 = 25
∴ r = 5 cm
Perimeter of sector = 2r + S
But perimeter is given to be 20 cm.
∴ 20 = 2(5) + S
∴ 20 = 10 + S
∴ S = 10 cm
Area of sector = 1/2 x r x S
= 1/2 x 5 x 10
= 25sq.cm.