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in Trigonometry by (25.9k points)
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If sec θ = m and tan θ = n, then \(\frac{1}{m}\left\{(m + n) + \frac{1}{(m + n)}\right\}\) is equal to

1/m{(m + n) + 1/(m + n)}

(A) 2 

(B) mn 

(C) 2m 

(D) 2n

1 Answer

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by (25.7k points)
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Best answer

Correct answer is (A) 2

Explanation :

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