Radius of curvature of convex mirror, R = 30 cm.
Focal length of convex mirror, f=R/2=30cm/2=15cm
Now h=5cm,u=-20cm,v=?,h'=?
Using the mirror formula 1/f=1/u+1/v, we have
1/v=1/f=1/u=1/15=1/-20=1/15+1/20=(4+3)/60
v=60/7=8.6cm.
Thus, image is formed at a distance of 8.6cm behind the convex mirror. The image is virtual and erect.
m=h'/h=-v/u
h'/5=-8.6/(-20)
h'=8.6/20x5=2.15cm.
Thus, the size of the image is 2.15 cm u,which is positive. It indicates that the image formed is erect, virtual and diminished.