(A) \(6.022 × 10^{20}\)
As we know,
\(1\,cm^3=1\,ml\)
\(\therefore 22.4\,cm^3=22.4\,ml\)
The volume of 1 mole of a gas at STP = 22400 ml/mol
\(\therefore\) Number of moles of \(O
_3\) gas = \(\frac{22.4\,ml}{22400\,ml/mol}\)
= \(10^{-3}\) moles.
\(\because\) 1 mole of \(O_3\) molecule contain = \(6.022\times10^{23}\) \(O
_3\) molecules.
\(\therefore 10^{-3}\) moles of \(O_3\) molecule contain = \(6.022\times10^{23}\times10^{-3}\) \(O
_3\) molecules.
= \(6.022\times10^{20}\) \(O_3\) molecules.
