# Prove that $\tan (x+h)=\tan x+h \sec ^{2} x+\frac{h^{2}}{2 !} 2 \sec ^{2}+\tan x+\frac{h^{3}}{3 !}$ $2 \sec ^{2} x \cdot \tan x$

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Prove that $\tan (x+h)=\tan x+h \sec ^{2} x+\frac{h^{2}}{2 !} 2 \sec ^{2}+\tan x+\frac{h^{3}}{3 !}$ $2 \sec ^{2} x \cdot \tan x$