Question

A piece of copper having a rectangular cross-section of 15.2 mm × 19.1 mm is pulled in tension with 44500 N forces producing only elastic deformation. Calculate the resulting strain.

(Rigidity modulus of copper = 42 × 10⁹ N m^-2)

Answer 1

Given: A = 15.2 × 19.14 × 10^-6 m²,

F = 44500 N, n = 42 × 10⁹ N m^-2

To find: Strain (θ)

Formula: n = \(\frac{F}{A\theta}\)

Calculation: From formula,

The strain produced in the piece of copper is 3.64 × 10^-3