Question

What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO₃ is mixed with 50 mL of 5.8% NaCl solution?

(Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5)

(a) 3.5 g

(b) 7 g

(c) 14 g

(d) 28 g

Answer 1

The correct option is (b) 7 g

Explanation

16.9% solution of AgNO₃, means 16.9 g of AgNO₃ in 100 mL of solution.

16.9 g of AgNO₃ in 100 mL solution = 8.45 g of AgNO₃ in 50 mL solution.

Similarly. 5.8% of NaCl in 100 mL solution = 2.9 g of NaCl in 50 mL solution.

The reaction can be represented as :

AgNO₃ + NaCl → AgCl + NaNO₃