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The coefficient of static friction between a block of mass 0.25 kg and a horizontal surface is 0.4. Find the horizontal force applied to it.

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The coefficient of static friction between a block of mass 0.25 kg and a horizontal surface is 0.4. Find the horizontal force applied to it.

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Given: μS = 0.4, m = 0.25 kg, g = 9.8 m/s2

To find: Force (FL)

Formula: FL = μSN = μS(mg)

Calculation: From formula,

FL = 0.4 × 0.25 × 9.8 = 0.98 N

The horizontal force applied to it is 0.98 N.

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