Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
84 views
in Physics by (37.6k points)
closed by

The Mariana trench is located in the Pacific Ocean and at one place it is nearly 11 km beneath the surface of water. The water pressure at the bottom of the trench is about 1.1 × 108 Pa. A steel ball of initial volume 0.32 m is dropped into the ocean and falls to the bottom of the trench. What is the change in the volume of the ball when it reaches the bottom?

(K = 1.6 × 1011 N/m2)

1 Answer

+1 vote
by (36.8k points)
selected by
 
Best answer

Given: V = 0.32 m3, K = 1.6 × 1011 N/m2,

P= 1.1 × 108 Pa, Patm = 1.01 × 105 Pa

∴ dP = PW – Patm = 1.1 × 108 – 1.01 × 105 ≈ 1.1 × 108 Pa

As, bulk modulus is given as,

K = V × \(\frac{dP}{dV}\)

∴ dV = 2.2 × 10-4 m3

The change in the volume of the ball when it reaches the bottom will be 2.2 × 10-4 m3.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...