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A force of 1 N doubles the length of a cord having cross-sectional area 1 mm^2. The Young’s modulus of the material of cord is

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A force of 1 N doubles the length of a cord having cross-sectional area 1 mm2. The Young’s modulus of the material of cord is

(A) 1 N m-2

(B) 0.5 × 106 N m-2

(C) 106 N m-2

(D) 2 × 106 N m-2

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1 Answer

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by (36.9k points)

Correct option is: (C) 106 N m-2

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