# When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l).

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When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:

(A) $\frac{1}{2}$Mgl

(B) $\frac{1}{2}$MgL

(C) Mgl

(D) MgL

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(A) $\frac{1}{2}$Mgl

elastic potential energy: $\frac{1}{2}$ × F × L = $\frac{1}{2}$Mgl