Answer: (b) [LT-2], [L] and [T]
According to the principle of dimensional homogeneity
Dimension of v = dimension of at = dimension of \(\frac{b}{t+c}\)
Dimension of a =\(\frac{\mathrm{[v]}}{[t]}=\frac{LT_2}{T}=[LT^{-2}]\)
Dimension of b =[v][t]=[LT-1T]=[L]
Dimension of c = [t]=[T]