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Two metal wires ‘P’ and ‘Q’ of same length and material are stretched by same load. Their masses are in the ratio m1 : m2. The ratio of elongations of wire ‘P’ to that of ’Q’ is

(A) \(m^2_1:m^2_2\)

(B) \(m^2_2:m^2_1\)

(C) m2 : m1

(D) m1 : m2

1 Answer

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Best answer

(C) m2 : m1

Since m = ρV

= ρ × A × t

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