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The increase in energy of a metal bar of length ‘L’ and cross-sectional area ‘A’ when compressed with a load ‘M’ along its length is (Y = Young’s modulus of the material of metal bar)

(A) \(\frac{FL}{2AY}\)

(B) \(\frac{F^2L}{2AY}\)

(C) \(\frac{FL}{AY}\)

(D) \(\frac{F^2L^2}{2AY}\)

1 Answer

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Best answer

(B) \(\frac{F^2 L}{2AY}\)

U = \(\frac{1}{2}\) × F × l

\(\frac{1}{2}\) × F × \(\frac{FL}{AY}=\frac{F^2 L}{2AY}\)

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