Let \(\sqrt{2(1-\sqrt3i)}\) = a + bi, where a, b ∈ R.
Squaring on both sides, we get
2(1 – √3 i) = a2 + b2 i2 + 2abi
2 – 2√3 i = (a2 – b2 ) + 2abi ….[∵ i2 = -1]
Equating real and imaginary parts, we get
a2 – b2 = 2 and 2ab = -2√3
a2 - b2 = 2 and b = \(-\frac{\sqrt3}a\)